Question

A and B together can do a piece of work in 16 days and A alone can do it in 48 days.

How long will B take to complete the work?​

Answer 1

Step-by-step explanation:

b will take 45 days plz mark me the branliest please

Answer 2

A very easy and simple trick.

A+B=16 days

A=24 days

So, let's take LCM of 16 and 24. That's 48.

Notr: This 48 unit is the total work to be done.

So, A and B do (48/16) = 3 unit work/day …(1)

And, A does (48/24) = 2 unit work/day …(2)

Equation(1)-(2)

{A+B-A=3–2=1}

B does (3–2)= 1 unit/day

So, Total days required = (Total work)/(unit per day)

That is B can do it in (48/1)=48 days.

Thanks