Math, asked by Knhf9817, 10 months ago

A and b together can do a piece of work in 20/3 days;but b can alone can do it in 12 days. How long will a take to do it alone?

Answers

Answered by rithinv78
9

Answer:

15 days

Step-by-step explanation:

A+ B takes 20/3 days

B alone 12 days

so total work = LCM(20/3,12) = 60

efficiency of A+B = 60/(20/3) = 9

efficiency of B= 60/12= 5

so A alone take 60/(9-5)= 60/4 = 15 days to complete the work

Answered by yenula
2

Step-by-step explanation:

Therefore “B” can do the work alone in 30 - days. A alone can do a piece of work in 25 days and B alone can do it in 30 days. They work together for 5 days, and then B leaves the work. In how many days will A finish the remaining work

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