A and B together can do a piece of work in 20 days, B and C together can do it in 15 days,
C and A together can do it in 12 days.
(1) How long will they take to finish the work, working all together?
(2) How long would each take to do the same work?
Answers
Answer:
A&B=20
B&C=15
C&A=12
According to L.C.M of 20,15,12
we get 60.
That means
A & B can do 3 units of work in 1 day.(A+B= 3)
B & C can do 4 units of work in 1 day.(B+C=4)
C & A can do 5 units of work in 1 day.(C+A=5)
3+4+5 =12
2(A + B+ C) = 12
A+B+C =6
(A+B)+C=6
3+C=6
C=3 per day
C can do 3 units of work per day,So In How many days it will take to complete 60 units of work??
DAYS ————— ———1 (?)
Total units of work——-3 (60)
(60/3)*1=20
C=20 days
A+B+C =6
A+(B+C)=6
A+4=6
A=2 per day
A can do 2 units of work per day,So In How many days it will take to complete 60 units of work??
DAYS ————— ———1 (?)
Total units of work——-2(60)
(60/2)*1=30
A=30 days
A+B+C=6
B+(C+A)=6
B+5=6
B=1 per day
B can do 1 unit of work per day,So In How many days it will take to complete 60 units of work??
DAYS ————— ———1 (?)
Total units of work——-1(60)
(60/1)*1=60
B=60 days
A can take 30 days
B can take 60 days
C can take 20 days to complete the work.
Hope will be helpful ☺️
Step-by-step explanation:
A and B = 20
B and C = 15
C and A = 12
(1) 2x(A and B and C )= 20+15+12
A and B and C =47
2
A and B and C= 23¹/² days
(2) A = ( A +B+C) - (B+C)
A = 23¹/² -15
A=47/2-30/2
A=17/2.
A=8.5
B= A+B+C - A+C
B=47/2-12
B=47/2-24/2
B=23/2
B=11.2
C=A+B+C -A+B
C=47/2-20
C=47/2-40/2
C=7/2
C=3.5
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