a and b together can do a piece of work in 20 days whereas b and c together can do same work in 15 days if a,b and c together can finish this work in 10 days then find the number of days in which b alone can finish the work
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Answer:
a+b=20days
b+c= 15days
a+ b +c=10days
then L.C.M 20,15,10=60days
a+b=3 a+ b +c=6
b+c=4
a=2, b=1 c=3
B = 60/1=60days
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