Question

A and B together can do a piece of work in 3 days. If A does thrice as much work as B in a given time, find how long A alone would take to do the work?

Answer 1

Answer:

the time taken by B =x

the time taken by A=3x

=A+B=3days

=3x+x=3

=4x=3

=x=3/4

therefore,

A=3/4×3

A= 1/4

Answer 2

Answer:

4 days

Step-by-step explanation:

let the work done by B be denoted by w

so A does the work equal to 3w

so total work is 4w

A takes 3 days to do work equal to 3w

so A will take 4*3/3=4days of work.