Question

A and b together can do a piece of work in 30 days a having worked for 16 days b finishes the remaining work alone in 44 days in how many days shall b finish the whole work alone

Answer 1

Answer:

Let A's 1 day's work = x and B's 1 day's work = y.

Then, x + y = 1 and 16x + 44y = 1.

30

Solving these two equations, we get: x = 1/60 and y = 1/60

B's 1 day's work = 1/60

Hence, B alone shall finish the whole work in 60 days.