A and b together can do a piece of work in 30 days. a having worked for 16 days, b finishes the remaining work alone in 44 days. in how many days shall b finish the whole work alone? select one:
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time taken by a to do the work = x
time taken by b to do the work = y
work done by a in a day=1/x
work done by b in a day=1/y
ATQ, 30/x +30/y =16/x+44/y
30/x-16/x=44/y-30/y
24/x=14/y
24y=14x
12y=7x
12/7=x/y
time taken by b to do the work = y
work done by a in a day=1/x
work done by b in a day=1/y
ATQ, 30/x +30/y =16/x+44/y
30/x-16/x=44/y-30/y
24/x=14/y
24y=14x
12y=7x
12/7=x/y
harshit0209:
Sorry this is incomplete
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