A and b together can do a piece of work in 30 days. A having worked for 16 days, b finishes the remaining work alone in 44 days. In how many days shall b finish the whole work alone?Lcm method
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Given that A and b together can do a piece of work in 30 days.
This implies in one day A and b together can do 1/30 of full work.
A works for 16 days and B works for 44 days alone.
Let A take x days and B take y days to complete the work alone.
Then one day contribution of A is 1/x and B is 1/y
16/x+44/y = 1 (since they complete full work by doing 16 and 44 days)
Also 1/x +1/y = 1/30 (since both together can do in 30 days)
Multiply II equation by 30 and subtract from first.
28/y = 14/30
Or y = 60 days
B takes 60 days to complete the project alone.
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