Question

A and B together can do a piece of work in 30 days . B and C together can do it in 20 days. A starts the work and works on it for 5 days and B takes up and works for 15 days.Finally C finishes the work in 18 days . The no:of days in which C alone can do the work when doing it separately is​

Answer 1

Answer:

A+B one day work = 1/30

B+C one day work = 1/20

A/q,

5A+15B+18C = 1

5A + 5B + 10B + 10C + 8C = 1

5(A+B) + 10(B+C) + 8C = 1

putting values we get,

5/30 + 10/20 + 8C = 1

8C = 1 - (1/6+1/2)

8C = 1 - (4/6)

8C = 1 - 2/3

8C = 1/3

C = 1/24

so, C complete the total work in = 24 days (Ans)

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