A and B together can do a piece of work in 35 days,while A alone can do it in 60days.How long would B alone take to do it?
Answers
Answered by
95
A+B = 35 days
in one day = 1 ÷ 35
A alone = 60 days
1 day = 1÷60
then B = ( 1÷35) - (1÷60)
= 12 - 7 ÷ 420
= 5 ÷ 420
=1 ÷ 84
thus B= 84 days
in one day = 1 ÷ 35
A alone = 60 days
1 day = 1÷60
then B = ( 1÷35) - (1÷60)
= 12 - 7 ÷ 420
= 5 ÷ 420
=1 ÷ 84
thus B= 84 days
Answered by
27
Step-by-step explanation:
A+B piece a work =35 days
in one day =1/35
A alone can do the same work =60 days
1 day = 1/60
then B alone can do the work = 1/35-1/60
17-7/420=5/420
5/420 then divide it then you will came =1/84
1/84 reciprocal it then it will came 84
Answer is 84 days
Similar questions