A and B together can do a piece of work in 4 hours
which A alone can do in 12 hours. In what time
could B alone do it?
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Answer :
B alone can complete the work in 6 hours.
Step-by-step explanation :
To Find,
- In how much time B alone can finish the work
Solution,
Given that,
- A and B together can do a piece of work in 4 hours
- A alone can do in 12 hours.
Therefore,
( A + B )'s 1 hour's work = 1/4
A's 1 hour work = 1/12
B's 1 hour's work = [ ( A + B )'s 1 hour's work ] - ( A's 1 hour's work )
» ( 1/4 - 1/12 )
» ( 3 × 1 ) - ( 1 × 1 ) / 12
» 3 - 1 / 12
» 2/12
» 1/6
Therefore, B can alone complete the work in 6 days.
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