A and B together can do a piece of work in 6 days,
B alone could do it in 16 days. If B stops after 8
days, how long afterwards will A have finished the
work? solve by lcm method
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Answer:
A+B- 6
B-16
ONE DAY WORK BY A+B IS 8
ONE DAY WORK BY B IS 3
I. E. ONE DAY WORK BY A IS 5.
TOTAL WORK IS 48
WORK DONE BY B IS 8*3=24
REMAINING WORK DOBE BY A =24/5 DAYS
Step-by-step explanation:
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