Math, asked by simranmishra474, 10 months ago

A and B together can do a piece of work in 6 days,
B alone could do it in 16 days. If B stops after 8
days, how long afterwards will A have finished the
work? solve by lcm method ​

Answers

Answered by nidhichaudharyb440
1

Answer:

A+B- 6

B-16

ONE DAY WORK BY A+B IS 8

ONE DAY WORK BY B IS 3

I. E. ONE DAY WORK BY A IS 5.

TOTAL WORK IS 48

WORK DONE BY B IS 8*3=24

REMAINING WORK DOBE BY A =24/5 DAYS

Step-by-step explanation:

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