a and b together can do a piece of work in 6 days. If a's 1 day work be 3/2 times the one days work of b, find how many days, each alone can finish the work?
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Answer:
10 & 15 days respectively.
Step-by-step explanation:
If B's efficiency is 2 then A's efficiency is 2*3/2 = 3.
If the total work is 30 the days A will require to complete the work is 30/3 = 10 days
and the days B will require to complete the work is 30/2 = 15 days.
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