Question

A and B together can do a piece of work in 6 days .If A's one day 's work be 3/2 times the one day's work of B ,find in how many days ,each alone can finish the work .​

Answer 1

Answer:

Let A completes the work in x days alone

Let B completes the work in y days

A's one day work=1/x B's one day work k = 1 / y

(A+B)'s one day work =1/x +1/y

A & B completes the work in 3/2

So 1/x + 1/y=1/6-------(1)

A's one day work k = 3/2 times of B's one day work

1 / x = 3/2 * 1 / y = 3/2 * y

Substituting 1 / x = 3/2 * y in eqn (1)

30 = 2y

Y = 15

And similarly substitute y value we get x=10