Question

A and B together can do a piece of work in 6 days. If B alone can finish it in 8 days, then A alone can do the work in how many days?

Answer 1

Hope u like my process
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=> Let A alone can do a work in x days

=> B alone can do a work in 8 days.

=> in 6 days A can do $\frac{1}{x} \times 6 = \frac{6}{x}$ Part of work

=> in 6 days B can do, $\frac{1}{8 } \times 6 = \frac{3}{4}$ Part of work.
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Thus,.. By problem,
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$= > \frac{6}{x} + \frac{3}{4} = 1 \\ \\ = > \frac{6}{x} = 1 - \frac{3}{4} = \frac{1}{4} \\ \\ = > \bf x = 6 \times 4 = 24$
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So

A alone can do a work in 24 days.
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Hope this is ur required answer

Proud to help you

Answer 2

A and B can do the work in 6 days

⇒ 1 day = 1/6 of the work

B can do the work in 8 days

⇒ 1 day = 1/8 of the work

Find the number of days needed for A to do it alone:

1 day = 1/6 - 1/8 = 1/24 of the work

1/24 of the work = 1 day

24/24 of the work = 1 x 24 = 24 days

Answer: A can do the work in 24 days.