Question

A and b together can do a piece of work in 60 days, a and c can do the same work in 45 days. the ratio of work efficiency of b and c is 1:2. in how many days they together can do the same work?​

Answer 1

Answer:

The answer is 36 days

Step-by-step explanation:

Let efficiency of b and c be = 1x and 2x

Work done by A + B in 1 day = $\frac{1}{60}$ parts

Work done by A + C in 1 day = $\frac{1}{45}$ parts

On subtracting both we get,

(A+B) - (A+C) = $\frac{1}{45} - \frac{1}{60}$

C -B = $\frac{1}{180}$ parts

2x - x = $\frac{1}{180}$

B = x = $\frac{1}{180}$

C = 2x = $\frac{2}{180}$ = $\frac{1}{90}$

Work done by A + B + C in 1 day = $\frac{1}{60}$ +  $\frac{1}{90}$ = $\frac{5}{180}$ = $\frac{1}{36}$ parts

Complete work done by A, b and c together = 1÷ $\frac{1}{36}$  = 36 days