A and B together can do a piece of work in 7 days if A alone does twice as much work as B in a work in a given time find how long A alone would take to the work work ?
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Answer: 14 days
Step-by-step explanation:
Let work of A = x, and B = y:-
As per the question,
Equations are:-
x + y = 7 ... (1), and
2x = y -7 ... (2)
In (2):-
2x + y = -7
SUBTRACTING (1) by (2):-
(2x + y ) - (x + y) = 7 - (-7)
Thus, x = 14
Thus A takes 14 days
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