A and B together can do a piece of work in 7 days. if A does twice as much work as b in a given time, find how long A alone would take to do the work
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A and B are the worker doing work in 7 days.
let the individual work of B in one day be 1/x
And therefore B is 2/X
1/x+2/x=1/7
3/x=1/7
x=21 days
So the work done by B=21 days individually and A P Q we know A=2/21
let the individual work of B in one day be 1/x
And therefore B is 2/X
1/x+2/x=1/7
3/x=1/7
x=21 days
So the work done by B=21 days individually and A P Q we know A=2/21
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