Math, asked by debabrata21, 1 year ago

A and B together can do a piece of work in 7 days. if A does twice as much work as b in a given time, find how long A alone would take to do the work​

Answers

Answered by priya4565
6
A and B are the worker doing work in 7 days.

let the individual work of B in one day be 1/x

And therefore B is 2/X

1/x+2/x=1/7

3/x=1/7

x=21 days

So the work done by B=21 days individually and A P Q we know A=2/21
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