Question

A and B together can do a piece of work in 8 days. B alone can do it in 12 days. B alone works at it for 4 days. In how many more days after that could A alone complete it.​

Answer 1

Answer:

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A alone can do

1/8 – 1/12 = 1/24 of the work in 1 day, i.e., A alone can do the same work in 24 days.

B's days' work = 1/12

=> B's 4 days' work

= 4/12 = 1/3

Therefore remaining 2/3 of the work is done by A alone in 2/3 × 2/4 = 16 days.