Question

A and B together can do a piece of work in 8 days but a alone can do it in 12 days how many days would B alone take to do the same work​

Answer 1

Answer:

total time taken by a and b is equal to 1÷8

Time taken by A is equal to 1÷12

So time taken by b is equal to (1÷8)-(1÷12)which is equal to

$1 \div 8 - 1 \div 12$

$1 \div 36$

Answer 2

Step-by-step explanation:

• (A + B) = 8 Days

• A = 12 Days

• B = ?

$\underline{\bigstar\:\textsf{According to the given Question :}}$

$:\implies\sf B=\dfrac{(A+B) \times A}{A-(A+B)}\\\\\\:\implies\sf B = \dfrac{8 \times 12}{12 - 8}\\\\\\:\implies\sf B = \dfrac{8 \times 12}{4}\\\\\\:\implies\sf B = 2 \times 12\\\\\\:\implies\underline{\boxed{\sf B = 24 \:Days}}$

⠀

$\therefore\:\underline{\textsf{B can alone do the work in \textbf{24 Days}}}.$