A and B together can finish a job in
20 days. B and C together can finish
the same job in 30 days. If A and C
together can finish it in 24 days, in how
many days can A alone finish the job?
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Answer:
Step-by-step explanation:
A+B takes 20 days
B+C takes 30 days
Since A is twice as efficient as C we can rewrite equation (1) as
2C+B takes 20 days, B+C takes 30 days
Let the total unit of work be 60
B+C one day work = 60/30=2
2C+B one day work = 60/20=3
(4)-(3) gives C’s one day work i.e 1
C will take 60/1 =60 days
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