A and B together can finish a piease of work in 12 days .lf A alone can finish the same work in 20 days in how many
B alone can finish it.
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Answer:
A can do a work in = 20 days
Let B can do the work in =X days
Both A and B can do the work in = 1/12 days
Therefore 1/20 + 1/X= 1/12
So 12 (X+20) = 20 X;
So 8X= 240 ; X= 30.
Therefore “B” can do the work alone in 30 - days.
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Another Simple Method:
In 12- days A- can complete= 12/20= 3/5- part of the work.
So in 12- days B- can complete (1–3/5) = 2/5- part of the work.
So complete work can be done by B- alone in 12÷ (2/5)= 12 x5/2= 30- days.
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