A and B together can finish a piece of work in 12 days. if A takes 10 days less than the time taken by B to finish the same work then find how long will each take separately to finish the same work
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b=x days
a=x-10 days
x +x-10=12
2x-10=12
2x=12+10
2x=22
x=22÷2
x=11
better you ask to your teacher or search in google
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