A and B together can finish a piece of work in 12 days if A alone can finish the same work in 20 days in how many days B alone can finish it
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A+B one day work = 1/12
A one day work = 1/20
1/12=1/20+1/x (where x = days taken by B to complete the work alone)
1/12=(x+20)/20x
20x/12=x+20
20x=12(x+20)
20x=12x+240
20x-12x=240
8x=240
X=240/8
=30 days
A one day work = 1/20
1/12=1/20+1/x (where x = days taken by B to complete the work alone)
1/12=(x+20)/20x
20x/12=x+20
20x=12(x+20)
20x=12x+240
20x-12x=240
8x=240
X=240/8
=30 days
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