Question

A and B together can finish a piece of work in 12 days. If‘A’alone can finish the same
work in 20days, in how many days B alone can finish it?​

Answer 1

Answer:

I don't know the answer I am sorry or not

Answer 2

Explanation:

Let B take x number of days.

A and B together take 12 days, meaning they complete 1/12 of the work in one day.

Similarly, A completes the work alone in 20 days, meaning he completes 1/20 of the work in one day.

Finally, B completes the work in x days, which means that he completes 1/x of the work in one day.

Work done by A and B together in 1 day = Work done by A alone in 1 day + Work done by B alone in 1 day

==>  $\frac{1}{12}=\frac{1}{20}+\frac{1}{x}$

==> $\frac{1}{12}=\frac{20+x}{20x}$

==> $20x = 12(20+x)$

==> $20x = 240 + 12x$

==> $20x - 12x = 240$

==> $8x = 240$ ==> $x = \frac{240}{8}$

∴ x = 30

Hence, B takes 30 days to finish the work alone.

Answer: 30 days

I hope this helps. :D