A and B together can finish a piece of work in 12 days. If "A" alone can finish the same work in 20 days , in how many days B alone can finish it ?
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Answered by
126
as we know a person one day work is equal to 1/n of total work where n is number of days
therefore a+b is equal to
1/a of the total work+1/b of the total work =1/12(as we calulate per day )
1/20+1/b of the total work =1/20 (as they gave as a alone can do in 20 days)
1/b of the total work =1/20-1/12
1/b of the total work =as LCM is 60 we get 3-5/60
1/b of the total work=-2/60 ⇒-1/30
therefore as b one day work is 1/30 the total work is equal to 30 days
⇒b works in 30 days
therefore a+b is equal to
1/a of the total work+1/b of the total work =1/12(as we calulate per day )
1/20+1/b of the total work =1/20 (as they gave as a alone can do in 20 days)
1/b of the total work =1/20-1/12
1/b of the total work =as LCM is 60 we get 3-5/60
1/b of the total work=-2/60 ⇒-1/30
therefore as b one day work is 1/30 the total work is equal to 30 days
⇒b works in 30 days
Answered by
45
b will complete the work in 30 daye ie 1 month
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