A and B together can finish a piece of work in12 days .if A alone can complete in 20 days in how many days does B complete
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A and B together can finish a piece of work in 12 days
so, A + B = 12 days
A and B together can finish work per day
so, A + B = 1/12..........(1)
if A can complete in 20 days
so, A = 20 days
A's work per day
A = 1/20 substitute in (1)
1/20+B = 1/12
B = (1/12) - (1/20)
B = 1/4(1/3 - 1/5)
B = 1/4((5-3)/(5×3))
B = 1/3(2/15)
B = 2/45
so, B's one day work is 2/45
so, B's work for 45/2 = 22.5 days
so, A + B = 12 days
A and B together can finish work per day
so, A + B = 1/12..........(1)
if A can complete in 20 days
so, A = 20 days
A's work per day
A = 1/20 substitute in (1)
1/20+B = 1/12
B = (1/12) - (1/20)
B = 1/4(1/3 - 1/5)
B = 1/4((5-3)/(5×3))
B = 1/3(2/15)
B = 2/45
so, B's one day work is 2/45
so, B's work for 45/2 = 22.5 days
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