Question

A and B together complete a job in 16 days while B and C together finish the job in 24 days if A is thrice as efficient as C in how many days will all of them working together complete the job
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Answer 1

Answer:

A+B=16

B+C=24

So A+C=40

A IS THRICE OF C

C=10

SO, A+B+C=16+24+10=50

Answer 2

Answer:

96/7

Step-by-step explanation:

A+B = 16 days

B+C = 24 days (LCM =48)

Efficiency of A+B = 3

Efficiency of B+C = 2

A’s efficiency = 3-B

C’s efficiency = 2-B

A’s efficiency =3-B which is equal to 3 (2-B)

3- B = 6 - 3B

2B = 3 Hence B=1.5 and hence C’ s efficiency =0.5 and A’s efficiency = 1.5

Total A+B+C Efficiency = 3.5

Total work =48 ÷ 7/2 =96/7