A and B together finish a wor in 20 days.They worked together for 15 days and then B left. Afer another 10 days,A finished the remaining work. In how many days A alone can finish the job?
A) 30 B) 40 C) 50 D) 60
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Answer:
A and B one day work = 1/20
portion of work completed by them in 15 days working together
=> 1/20*15 = 15/20 = 3/4
remaining work after 15 days
=> 1 - 3/4 = 1/4
[ total work has to be taken as one unit ]
Remaining work of 1/4 completed by
A = 10 days
=> A's one day work = 1/4*1/10 = 1/40
therefore reciprocal of A's one day work gives number of days required to complete the work
reciprocal of A's one day work = 40
hence A alone can complete the work on 40 days
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