Question

A and B tuning folks produce 5 beats per second . 'A' equal
to 250 Hz. On loading B' with wax the beat
frequency becomes 6. Then find the intial and
final frequencies of 'B'.​

Answer 1

Answer:

folks A. floks B. beats

250. it's should be rather 5

245 or 255

250. 256 or 244. 6

Explanation:

so the wax is deposited the the beat will decrease 245

Answer 2

Answer:

244Hz

Explanation:

|A-B|=5

A=250----(1)

On loading, frequency decreases, so when we loaded B, beat frequency increased, i.e when B decreased, |A-B| increased

which suggests that A>B

∴A-B=5----(2)

Using (1) and (2);

B=245Hz

Final frequency of B after loading with wax is

A-B'=6---(3)

Using (1) and (3);

B'=244Hz

Hope this answer helped you :)