Question

a and b two consecutive negative integers and a^2-b^2=91 find the value of a+b
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Answer 1

hope the answer helps you:)

Answer 2

Answer:

let a and b are the numbers from the given condition a^2-b^2 and a,b are negative integers

we conclude that b be the larger one

so b-a =1

given

a^2-b^2=91

(a+b)(a-b)=91

-(a+b)(b-a)=91

(a-b)= -91