A and B walk around a circular track. They start at 8 a.m. from the same point in the
opposite directions. A and B walk at a speed of 6 rounds per hour and 4 rounds per hour
respectively. How many times shall they cross each other before 11.45 a.m. (approx)?
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Answer:
7 times
Step-by-step explanation:
Let us treat circular motion in degrees. 1 round = 360°
Speed of A
= 2 round/hr. = 720° in 60 min = 360° in 30 min
= (360°/30) in 1 min.
= 12° / min.
Speed of B
= 3 round/hr. = 1080° in 60 min = 540° in 30 min
= (540°/30) in 1 min.
= 18° / min.
Since A and B are moving in the opposite directions, they complete 360° together, while crossing each other.
Let it take n minutes to make a round (360°) together.
n (12°+18°) = 360°
n=360°/30°
n=12
They cross each other once in 12 minutes.
Between 8:00 am to 9:30 am, there are 90 minutes.
The number of crosses = 90/12 = 7.5
Ans: They will cross each other 7 times before 9.30 am
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