Question

A and B will do one work in 15 days and B and C will do the same work in 12 days and C and A in the same day within 10 days.​

Answer 1

Answer:

(A+B)=1/15

(B+C)=1/12

(C+A)=1/10

2(A + B + C)=1/2(1/15+1/12+1/10)=1/2(6+4+5/60)=1/2(15/60)=1/8

together a,b,c can finish in 8 days.

A=(A + B+C) - ( B+C) =1/8-1/12=3-2/24=1/24

B= (A + B + C ) - ( A + C)

=1/8-1/10=5-4/40=1/40

C=(A+B+C)- (A+B)

=1/8-1/15=15-8/120=7/120

A=24days,B=40days,c=120/7

Answer 2

Answer:

hey a+b+c=7.5

b+c=5

substitute

a=7.5-(b+c)

a=2.5

Step-by-step explanation:

A+B = 15

B+C = 12

A+C = 10

Lcm of (12,15,10) = 60

Efficiency is  

A+B = 4

B+C = 5

A+C = 6

Total efficiency

2 (A+B+C) = 15

A+B+C = 15/2

Individual efficiency

A = 7.5-5=2.5

B = 7.5 - 6 = 1.5  

C = 7.5 - 4= 3.5

Individual time taken

A = 60/2.5 = 24 days

B =60/1.5 = 40 days  

C = 60/3.5 = 17 days