Question

A and B worked together, but A leaves the job after 2 days. How much work is still left?
(no spamming)​

Answer 1

(A+B)'s one day's work = 1/3 part;

(A+B)'s one day's work = 1/3 part;(A+B) works 2 days together = 2/3 part;

(A+B)'s one day's work = 1/3 part;(A+B) works 2 days together = 2/3 part;Remaining work = 1-(2/3) = 1/3 part;

(A+B)'s one day's work = 1/3 part;(A+B) works 2 days together = 2/3 part;Remaining work = 1-(2/3) = 1/3 part;1/3 part of work is completed by A in two days;

(A+B)'s one day's work = 1/3 part;(A+B) works 2 days together = 2/3 part;Remaining work = 1-(2/3) = 1/3 part;1/3 part of work is completed by A in two days;Hence, one day's work of A = 1/6;

(A+B)'s one day's work = 1/3 part;(A+B) works 2 days together = 2/3 part;Remaining work = 1-(2/3) = 1/3 part;1/3 part of work is completed by A in two days;Hence, one day's work of A = 1/6;Then, one day's work of B = 1/3-1/6=1/6;

(A+B)'s one day's work = 1/3 part;(A+B) works 2 days together = 2/3 part;Remaining work = 1-(2/3) = 1/3 part;1/3 part of work is completed by A in two days;Hence, one day's work of A = 1/6;Then, one day's work of B = 1/3-1/6=1/6;So, B alone can complete the whole work in 6 days.