Question

A and b working alone can do a piece of work in 20days 15days respecctively they started work together byt b left aftersometime and a finished remaining work in 6days find after howmany days from start b left

Answer 1

A,s one day work =

$\frac{1}{20}$

B, s one day work =

$\frac{1}{15}$

A and B together one day work =

$\frac{1}{20} + \frac{1}{15} = \frac{7}{60}$

let A and B together work for x days

so work done = 7x/60

A 6 day work = 6 * 1/20 = 3/10

remaining work = 1 - 3/10 = 7/10

now this work is completed by A and B together.

therefore 7x/60 = 7/10

x = 6

Answer 2

Answer:

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