Math, asked by Vikkyvikas6712, 1 year ago

A and b working separately can do a piece in 20 days and 30 days respectively. they worked together for sometime then b left the work. a completed the remaining work in 10 days, then b worked for how many days

Answers

Answered by chaudharyjat
2
1/20+1/30
3+2/60
5/60=1/12
12 answers
Answered by OS13
4
Hey!!!
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●In 1 day A can do 1/20 part of work
and in 1 day b can do 1/30 part of work
So,In 1 day both (A and B)can do 1/30+1/20=2+3/60=5/60 pow
And in 10 day A can do 1/20×10=1/2 pow
So,Remaining work=1-1/2=1/2
Hence,Remaining work done by both A and B in 1/2×60/5=6 days
That means B worked for 6 days
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Hope it helps!!! :)
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