A and B working separately can do a piece of work in 9 nd 15 days respectively if they work for a day alternately. with A beginning. then the work will be completed in how many days
Answers
Given:
A alone can do a piece of work in 9 days
B alone can do a piece of work in 15 days
A and B work on alternate days
To find:
The required no. of days in which the work will be completed
Solution:
We have,
In 1 day, the amount of work done by A will be
In 1 day, the amount of work done by B will be
As given in the question that A and B will be working separately on the alternate days starting with A, so let us first understand the pattern of their work i.e.,
A B A B A B ……..
From the above pattern, we can see that
- The amount of work done in 1st & 2nd day will be first done by A and then by B i.e., () of the total work
- The same amount of work will be done on the 3rd & 4th day, then on the 5th & 6th days and so on.
- From this, we get that the cycle will be repeated every 2 days.
∴ The amount of work done in the first 2 days,
Since nothing is specified in the question so we will consider the total work to be done is 1 unit of work.
Now, we will convert 8/45 unit of work into 1 unit of work
2 days → 8/45 units
8 is not a direct multiple of 45 so we will multiply 8 in such a way that it is as close as 45 i.e.,
we will multiply with 5 on both the sides
5 * (2 days) → 5 * (8/45 units)
10 days → 40/45 units of work are completed in 10 days
Since B has been working on every even no. of days, therefore, B has worked on the 10th day.
∴ The remaining amount of work to be done by A on the 11th day will be,
= 1 –
=
=
= units of the total work
We know that A does 1/9 units of work in 1 day
∴ The required time to complete the whole work = 10 + 1 = 11 days
Thus, the work will be completed in 11 days.
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