Question

A and b working separately can finish a work in 12 and 18 days- respectively. If they work together for 5 days and then a goes away, in how many days will b complete the work?

Answer 1

Answer:

Step-by-step explanation:

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Answer 2

B can complete the remaining work in 5.5 days

Step-by-step explanation:

A can do work in days = 12

A's 1 day work =$\frac{1}{12}$

B can do work in days = 18

B's 1 day work =$\frac{1}{18}$

So, (A+B)'s 1 day work = $\frac{1}{12}+\frac{1}{18}=\frac{5}{36}$

(A+B)'s 5 day work =$\frac{5}{36} \times 5 = \frac{25}{36}$

Remaining work = $1- \frac{25}{36}=\frac{11}{36}$

A left

So, B can do work in days = 18

So, B can do$\frac{11}{36}$work in days =$18 \times \frac{11}{36} = 5.5$

So, B can complete the remaining work in 5.5 days

#Learn more :

A can complete the work in 6 days . A & B working together can complete the work in 4 days . How long would B alone take to complete the work .

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