Question

A and B working together can do a piece of work in 10 days. B alone can do that work same work in 15 days. how long will a alone take to do the same work ?
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Answer 1

Step-by-step explanation:

A+B=10 ,B=15

then we find total work... to obtain total work we have to take LCM of 10 and 15

therefore LCM of 10 and 15 is 30

then we find strength of A+B and B alone

(A+B) strength=30/10=3

B strength=30/15=2

(A+B) =3

it means

A Strength+B strength=3

A strength +2 = 3

A strength=3-2=1

and at last we find the number of days taken by A

Day equal to total work divided by strength of A

Day=30/1= 30 days

answer

Answer 2

Answer:

this is the answer .................