A and B working together can do a piece of work in 4 1/2 hours B and C working together can do it in 3 hours c and a working together can do it in 2 to 1 /2 hours all of them begin the work at the same time find how much time take to
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Step-by-step explanation:
A and B can do work =4 and 1 half hour
B and c can do work in=3 hrs
C and A can do work in 2 and half hour
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Given that
A+B =4.5=9/2 days
B+C =. 3 days
C+A=2.5 =5/2 days
A+B ‘s one day work 2/9 < reciprocal for efficiency>..........eq1
Similarly,
B+C ‘s one day work 1/3.......eq2
C+A’s one day work 2/5 ......eq3
We have to find A+B+C’s efficiency(one days work )
Now , we know that time and efficiency are inverse proportional to each other
Add eq 1,2,3
== 2[A+B+C]= 2/9+1/3+2/5
So ==2[A+B+C] = 43/45
==A+B+C == 43/90
Time to complete work = 90/43
=2 4/43
Hope u like it
A+B =4.5=9/2 days
B+C =. 3 days
C+A=2.5 =5/2 days
A+B ‘s one day work 2/9 < reciprocal for efficiency>..........eq1
Similarly,
B+C ‘s one day work 1/3.......eq2
C+A’s one day work 2/5 ......eq3
We have to find A+B+C’s efficiency(one days work )
Now , we know that time and efficiency are inverse proportional to each other
Add eq 1,2,3
== 2[A+B+C]= 2/9+1/3+2/5
So ==2[A+B+C] = 43/45
==A+B+C == 43/90
Time to complete work = 90/43
=2 4/43
Hope u like it
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