A and B working together can do a piece of work in 6 days. A takes 5 days less than B to fnich the work. ish Let B takes x days to finish the work, then answer the following questions
Answers
Answer:
Step-by-step explanation:
Let us assume A did ‘a' work per day and B did ‘b' work per day.
Let us assume the total work be 30.( we can assume any number be total work)
Therefore the work completed by A and B together in a day is 30/6=5 i.e. a+b=5 a=5-b
It is given that A take 5 days less than B while working alone.
(30/b)-(30/a)=5
1/b-1/a=1/6
a-b=ab/6
6(a-b)=ab
6(5–2b)=5b-b^2
b^2–17b+30=0
(b-15)(b-2)=0
b=2
Since a+b=5 and a can not be negative.
Hence B can do 2 work pef day.
Therefore B alone can finish the total work of 30 in 30/2 =15 days.
》 satyam _bradwaj
A & B working together do work in 6 days.
A takes 5 days less than B.
Let B takes x
⇒A=x−5
x1+x−51=61
x2−5xx−5+x=61
12x−30=x2−5x
x2−17x+30=0
x2−15x−2x+30=0
x(x−15)−2(x−15)=0
(x−2)(x−15)=0
⇒x=2 or x=15
As, x<5 so x=15
then A=10 days &B=15 days
Hence, the answer is 10,15days