Question

A and B working together can do a piece of work in 6 days. B alone
can do it in 8 days. In how many days A alone could finish?​

Answer 1

Answer:

2

Step-by-step explanation:

a+b=can do it work

6-8=2

Answer 2

Question

A and B working together can do a piece of work in 6 days. B alone can do it in 8 days. In how many days A alone could finish?

Solution-

Time taken by ( A + B ) to finish the work = 6 days.

Time taken by B alone to finish the work = 8 days.

.°. ( A + B )'s 1 day's of work = $\sf\green { \frac{1}{6}}$

and B's 1 day's work = $\sf\green { \frac{1}{8} }$

.°. A's 1 day's work =

$\sf\red { [( A + B )'s \: day's \: work ] - [B's \: 1\: day's\: work ] }$

$\sf\red { = > ( \frac{1}{6} - \frac{1}{8} ) = \frac{4 - 3}{24} = \frac{1}{24}}$

.°. A alone can finish the work in 24 days.