Question

A and b working together can finish a piece of work in 6 days while alone a can do it in 9 days . how much time will b take to finish it

Answer 1

A's one day work = 1/9

A+B one day work = 1/6

Therefore 1/9+B one day work=1/6

B one day work = 1/6-1/9=1/18

Therfore B alone canfinish the work in 18 dys

Answer 2

Answer:

18 days

Step-by-step explanation:

Since, a alone do the work in 9 days,

So, the one day work of A = $\frac{1}{9}$

Also, both a and b do the work in 6 days,

⇒ The combined one day work of a and b = $\frac{1}{6}$

Thus, the one day work of b = The one day work of both a and b - One day work of a

$=\frac{1}{6}-\frac{1}{9}$

$=\frac{3-2}{18}$

$=\frac{1}{18}$

Hence, the time taken by b alone = $\frac{1}{\text{ His one day work}}$

$=\frac{1}{1/18}$

$=18\text{ days}$