Question

a. Anil runs around a square field of side 60 m four times. What distance does he cover?

b. Vinay runs twice a rectangular field with length 180 m and breadth 110m. What distance does he cover?

c. A square piece of ground is 75 m long. Find the cost of fencing around it

at Rs 4 per metre.

d. A wire is bent in the form of an equilateral triangle of each side 12 cm.If the same wire is bent in the form of a square, find the side of the square.

e. An equilateral triangle and a square have equal perimeters . If side of the square is 12 cm, what is the length of the side of the triangle?

f. Each side of a square is 30 cm and a rectangle has length 20 cm.If the perimeter of both (square and rectangle) are same, find the breadth of the


Find the area of :

a. The square with side length 8cm.

b. The rectangle with length- 20 cm and breadth- 5 cm. c. The rectangle with length- 1.6 m and breadth- 65 cm. d. The square with side length 10.5 cm.



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Answer 1

Answer:

1.a.960 m

 b. 1160 m

 c.1200 Rs.

 d.9 cm

 e.16 cm

 f.40 cm

2.a.64 square cm

 b.100 square cm

 c.10400 square cm

 d.110.25 square cm

Step-by-step explanation:

Q1.

a.60X4X4=240X4=960 m

b.(180+110)X2X2=290X4=1160

c.75X4X4=75X4=300mX4=1200 Rs.

d.perimeter of equilateral triangle=12X3=36cm

perimeter of square=36cm

side of square=36/4=9cm

e.side of square=12cm

perimeter=12X4=48cm

equilateral triangle=48cm in perimeter

side of triangle=48/3=16cm

f. square perimeter=30X4=120cm.

length of rectangle= 2(x+20)=120cm

= 2x+40=120cm

=120cm-40cm=2x

=80=2x=x=80/2=40

Q2.

a.area=8 squared=8X8=64 square cm.

b.area=lXb=20cmX5cm=100 square cm.

c.1.6m=160cm breadth=65cm

area=10400 square cm.

d.10.5 squared= area of square=110.25 square cm.