(a) Apply elementary row operations to transform the following matrix first into echelon form and then into reduced echelon form: 0 3-6 3 -7 64-5 8-58 9 3 -9 12 -9 6 15
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We have seen how to write a system of equations with an augmented matrix, and then how to use row operations and back-substitution to obtain row-echelon form. Now, we will take row-echelon form a step farther to solve a 3 by 3 system of linear equations. The general idea is to eliminate all but one variable using row operations and then back-substitute to solve for the other variables.
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