Chemistry, asked by devang652, 1 year ago

a aq naoh b (a ketone) i2 / naoh chi3 + sodium propanoatea aq naoh b (a ketone) i2 / naoh chi3 + sodium propanoate

Answers

Answered by GarmadonMaximus21

1

This is iodoform reaction.(mainly answered by methyl ketones and methyl carbinols)

Since sodium propanoate is liberated here, the ketone will be butan-2-one.

Ans-Butan-2-one

STRUCTURE

CH3-CO-CH2-CH3

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