a aq naoh b (a ketone) i2 / naoh chi3 + sodium propanoatea aq naoh b (a ketone) i2 / naoh chi3 + sodium propanoate
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This is iodoform reaction.(mainly answered by methyl ketones and methyl carbinols)
Since sodium propanoate is liberated here, the ketone will be butan-2-one.
Ans-Butan-2-one
STRUCTURE
CH3-CO-CH2-CH3
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