Question

a) Arbaz plans to tile his kitchen floor with
green square tiles. Each side of the tile is 10
cm. His kitchen is 220 cm in length and 180
cm wide. How many tiles will he need?​

Answer 1

$\sf\Large{\underline{\underline{Answer:-}}}$

Given,

• Side of the tiles = 10cm
• Length of Kitchen = 220cm
• Breadth of kitchen = 180cm

Find:-

• Tiles required?

⠀

|Finding the area of tiles and kitchen.|

✶Area of kitchen:-

Formula using here = $\bf{\underline\green{Length×breadth}}$

Substitute the values,

$\Longrightarrow$220 × 180

$\Longrightarrow$39600

Thus the area of kitchen is 39600cm².

Now,

⠀

✶ Area of tiles:-

Formula used here = $\bf{\underline\green{Side \: × \: Side}}$

Substitute the values,

$\Longrightarrow$10 × 10

$\Longrightarrow$100

Thus, the area of tiles is 100cm².

⠀

Then,

$\begin{gathered}\\\;\sf{:\rightarrow\;\;tiles \: required\;=\;\bf{\dfrac{area \: of \: kitchen}{area \: of \: tiles}\:}}\end{gathered}$

$\begin{gathered}\\\;\sf{:\rightarrow\;\;tiles \: required\;=\;\bf{\dfrac{39600}{100}\:}}\end{gathered}$

Tiles required = $\sf{\cancel\dfrac{39600}{100}}$

$\Longrightarrow$Tiles required = 396

$\sf\underbrace{Hence,}$

Arbaz need 396 tiles.

Answer 2

Given each side of the tile =10 cm

Area of one tile = (10×10)=100 cm2

And also given the length of kitchen =220 cm.

Breadth of kitchen =180 cm

Area of the kitchen floor =(l×b)

=(220×180)cm2

=39,600 cm2

Total no. of tiles needed,

= 39,600/10

= 396 tiles.

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