aß are zeroes of 2x²+5x-10 then the value of aß is?
Answers
Answered by
1
Answer:
-5
Step-by-step explanation:
alpha*beeta is c/a
so -10/2=-5
Answered by
1
Answer:
αβ=-5
Step-by-step explanation:
2x²+5x-10 are the zeros of polynomial
α+β=-b/a
αβ=c/a
a=2
b=5
c=-10
αβ=-10/2
αβ=-5
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