A area of a rectangular carpet is 120square m it's perimeter is 46 m so the length of it's diagonal is
Answers
Answer:
Area of the rectangular carper =120 cm
2
Perimeter =46 m
2(l+b)=46
(l+b)=46/2
l+b=23
And, length × breadth=120
Now, we know that :
(l−b)
2
=(l+b)
2
−4lb
(l−b)
2
=(23)
2
−4×120
(l−b)
2
=529−480
(l−b)
2
=49
(l−b)
2
=(7)
2
Hence, l−b=7
And l+b=23
By adding, we get 2l=30
l=30/2
l=15
and, b=23−15
b=8
Diagonal =
(l
2
+b
2
)
=
(15)
2
+(8)
2
=
(225+64)
=
(289)
=17 m
Step-by-step explanation:
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Area of the rectangular carper =120 cm2
Perimeter =46 m
2(l+b)=46
(l+b)=46/2
l+b=23
And, length × breadth=120
Now, we know that :
(l−b)2=(l+b)2−4lb
(l−b)2=(23)2−4×120
(l−b)2=529−480
(l−b)2=49
(l−b)2=(7)2
Hence, l−b=7
And l+b=23
By adding, we get 2l=30
l=30/2
l=15
and, b=23−15
b=8
ㅤㅤㅤㅤㅤㅤ______
Diagonal =_/(l2+b2)
ㅤㅤㅤ________
= ㅤ_/(15)2+(8)2
ㅤㅤ_______
= _/(225+64)
ㅤㅤㅤ______
=ㅤ_/ (289)
17m