a area of rectangle is 192 square and its perimeter is 56 cm find the dimensions of rectangle
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Answer:
area =192square cm
l*b=192
l=192/b
perimeter=56cm
2(l+b)=56
l+b=28
192/b+b=28
192+b^2=28b
b^2-28b+192=0
b^2-16b-12b+192=0
b(b-16)-12(b-16)=0
(b-16)(b-12)=0
b=16 or b=12
length=192/12=16cm
or
length=192/16=12cm
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